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Answer:

Key = 2001

h (2001) = 2001 % 19 = 6

g (2001) = 1 + [ 2001 % 18 ] = 1 + 3 = 4

H (2001, 0) = [ h (2001) + ( 0 ) g (2001) ] % 19 = [ 6 + ( 0 * 4 ) ] % 19 = 6 % 19 = 6

H (2001, 1) = [ h (2001) + ( 1 ) g (2001) ] % 19 = [ 6 + ( 1 * 4 ) ] % 19 = 10 % 19 = 10

H (2001, 2) = [ h (2001) + ( 2 ) g (2001) ] % 19 = [ 6 + ( 2 * 4 ) ] % 19 = 14 % 19 = 14

1. Suppose 2002 is to be inserted (using double hashing) after 2001 has been stored. Which slot will be used?

Answer:

Key = 2002

h (2002) = 2002 % 19 = 7

g (2002) = 1 + [ 2002 % 18 ] = 1 + 4 = 5

H (2002, 0) = [ h (2002) + ( 0 ) g (2002) ] % 19 = [ 7 + ( 0 * 5 ) ] % 19 = 7 % 19 = 7

H (2002, 1) = [ h (2002) + ( 1 ) g (2002) ] % 19 = [ 7 + ( 1 * 5 ) ] % 19 = 12 % 19 = 12

H (2002, 2) = [ h (2002) + ( 2 ) g (2002) ] % 19 = [ 7 + ( 2 * 5 ) ] % 19 = 17 % 19 = 17

H (2002, 3) = [ h (2002) + ( 3 ) g (2002) ] % 19 = [ 7 + ( 3 * 5 ) ] % 19 = 22 % 19 = 3

H (2002, 4) = [ h (2002) + ( 4 ) g (2002) ] % 19 = [ 7 + ( 4 * 5 ) ] % 19 = 27 % 19 = 8

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